JEE Main 2020 Paper with Solutions Physics 9th Jan Shift 2 JEE is an examination conducted for admission into some of the reputed organisations across the country. Download JEE Main 2020 Question Paper (7th January – Morning) with Solutions for Physics, Chemistry and Mathematics in PDF format for free on Mathongo.com. Step 2 – Match the question Id and check the correct answer ID in front of it. JEE Main 2020 Questions, Answer Key & Solutions We bring to you the JEE MAIN 2020 Answers and Solution Key. 2. ), A particle of mass m is revolving around a planet in a circular orbit of radius R. At the instant the particle has velocity , another particle of mass moving at velocity collides perfectly in-elastically with the first particle. The amount of oxygen required by bacteria to break down the organic matter present in a certain volume of a sample of water, is called Biochemical Oxygen Demand (BOD). 10–3 molar MgSO4 = 10–3 moles of MgSO4 present in 1 L solutions. The major product for above sequence of reaction is: Q5) Which of the following will give the highest yield to Friedel Craft's reaction? JEE Mains 2020 Question Paper for January Session (Paper 1) The JEE Main question papers for BE/Btech January exam along with the official answer keys are available for download. JEE Main 2020 is a computer-based test. Candidates will be able to check their correct answers and estimate their scores. If a circle touches y-axis at (0, 4) and passes through (2, 0) then which of the following can not be the tangent to the circle, (1) 3x + 4y – 6 = 0 (2) 3x + 4y – 24 = 0, (3) 4x – 3y – 17 = 0 (4) 4x + 3y – 6 = 0, Equation of family of circle touches at (0,4), This family of circle passes through (2,0), (1) 1.8 eV (2) 0.8 eV (3) 1.1 eV (4) 1.4 eV, and radius in terms of V can be written as :-, The kinetic energy of the particle is E and it's De-Broglie wavelength is . The Question paper is divided into 3 sections: Chemistry, Physics, and Mathematics. at 300 K and 40 min. National Test Agency( NTA) Is conducting JEE Mains 2020 Exam in two shifts, through an online mode. Q13) Write the correct order of basicity: Basicity is inversely proportional to electronegativity. Hence complex is Cr(H2O)6Cl3. (4) IV > I > II > III. Select the correct statements regarding this Then, kinetic energy changes but the momentum is constant, the momentum changes but the kinetic energy is constant, both momentum and kinetic energy of the particle are not constant, both, momentum and kinetic energy of the particle are constant. Find number of real roots of equation is? The exam duration is three hours and the exam consists of 300 marks (Maximum Marks). Then value of Through this article, you will get JEE main 2020 question paper with solution (Jan 8th second shift). https://www.collegedekho.com/articles/jee-main-january-question-papers (3) Hexaaquachromium(IV) chloride In this article, you will get JEE main 2020 question paper with solution (Jan 9th Second shift). NTA JEE Mains 2020 Answer Key Official for 6th,7th,8th,9th January with Shift Wise Question Paper (Paper 1 and 2): The National Testing Agency (NTA) is set to publish the Official JEE Main 2020 Answer Paper 1 & Paper 2 (shift 1 and 2). Bond dissociation enthalpy of bromine = y kJ/mole, (a) Does not exist Amd got least of all in chem. Which of the following statements are correct for moving charge as shown in figure. As a moment of inertia of one sphere of radius R about its centre=, Consider an infinitely long current carrying cylindrical straight wire having radius 'a'.Then the ratio of. (1) Cis-isomer. The gas is in thermal equilibrium with excess of 0.5 m aqueous ethylene glycol at its freezing point. in figure. The Mathematics section had most of the questions from Class 11th. Acceleration of particle varies with x–n then value of n is. density of H2O(l) = 1 g/ml. JEE Main 2020 Answer Key Allen Kota: JEE Main April Exam is being conducted from September 1 to 6, 2020.NTA is the conducting body of JEE Main. (I) Excess of NaOH (II) Dilute HCl, then volume ratio of H2 gas evolved in (I) and (II) is Q23. Q5. (C) Li and Mg react slowly with water. net Lorentz force on this charge at and when it is at origin. An electron (-|e|, m) is released in Electric field E from rest. Solution (3) [Xe]4f76s2, [Xe]4f15d16s2 (ii) Penetration power of 2s orbital is greater than 2p orbital The result of JEE Main is to be announced on 11th September. Number of gm of oxygen in 32.2 g Na2SO4.10H2O is ? JEE Main 2020 Question paper with answer key free pdf 8th January 2nd Shift. It has been conducted on 6th January 2020. In YDSE pattern with light of wavelength , 15 fringes are obtained on a certain segment of, screen. Now loop is slightly rotated about its diameter and released. If f(x) and g(x) are continuous functions, fog is identity function, g'(b) = 5 and g(b) = a then f'(a) is, A mass m attached to spring of natural length and spring constant k. One end of string is attached to centre of disc in horizontal plane which is being rotated by constant angular speed . Allen Kota JEE Main 2020 January session’s unofficial Answer key has been released by the Allen Kota coaching institute.The answer key will help students to study and prepare accordingly for the upcoming April session. Two electromagnetic waves are moving in free space whose electric field vectors are given by, A charge q is moving with velocity Find the. Then equation of magnetic field will be -, As we know that the axis of polarisation of the Em wave is same as Electric field direction that is -, And the equation of the electromagnetic waves will be in terms of the. If number of fringes for light of wavelength on same segment of screen is 10, then the value Different value of a, b and c are given and their sum is d. Arrange the value of d in increasing order -, Two gases Ar (40) and Xe (131) at same temperature have same number density. The JEE Main 2020 Question Paper with Solution (Jan 9th first shift) are provided by experts on the basis of memory-based JEE main 2020 questions provided by the aspirants. Given : Spin only magnetic moment = 3.8 B.M. Each Part has two sections (Section 1 & Section 2). The Authority is planning to upload the JEE 2020 Main Official Exam Paper Solution to the official website www.jeemain.nta.nic.in in this week. JEE Main Paper 2 is a widely known exam among B.Arch Aspirants. (iii) Shielding of 2p electron by 2s electron Non-metal oxides are acidic in nature These step by step solutions will help students to understand the problems easily. Let circles (x – 0)2 + (y – 4)2 = k and (x – 3)2 + (y – 0)2 = 12 touches each other than find the maximum value of 'k', Distance between C2(3, 0) and C1(0, 4) is either, Q10. Q1. JEE Main 2020 (Sep) – Question Paper, Key & Solutions 2nd September 2020 (Morning Shift) 2nd September 2020 (Evening Shift) 3rd September 2020 (Morning Shift) 3rd September 2020 (Evening Shift) 4th September 2020 (Morning Shift) 4th September 2020 (Evening Shift) 5th September 2020 (Morning Shift) 5th September 2020 (Afternoon Shift) 6th September 2020 (Morning Shift) … Free PDF Download of Online JEE Main 2020 Question Paper 9 January Morning with Solutions for Physics, Chemistry and Mathematics on Vedantu.com. JEE Main Paper 2 January exam was held on January 6, 2020. (A) reacts with (C) to form B3N3H3(CH3)3. An observer, towards whom the toy car is moving, is able to hear 5 beats per second. Q4. A (3,–1), B(1,3), C(2,4) are vertices of ABC if D is centroid of ABC and P is point of intersection of lines x + 3y – 1 = 0 and 3x – y + 1 = 0 then which of the following points lies on line joining D and P, Q18. (L = 40 mH, C = 100, screen. Morning Shift . Let both root of equation ax2 – 2bx + 5 = 0 are and root of equation x2 – 2bx – 10 = 0 are and . JEE Main 2020 9th Jan shift 1 solved Physics paper consists of accurate solutions, prepared by our subject experts. Greater the resonance of lone pairs lesser the basic strength. The Question paper is divided into 3 sections: Chemistry, Physics, and Mathematics. (2) Entropy is a function of temperature & entropy change is not a function of temperature. A toy-car, blowing its horn, is moving with a steady speed of 5 m/s, away from a wall. Q10) Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. The question paper consists of 3 Parts (Part I: Physics, Part II: Chemistry, Part III: Mathematics). JEE Main 2020 Answer Key and Question Paper PDF for September 1, 2 & 3 exam is now available. The last paper of JEE Main was conducted today January 9 in two shifts. Stay tuned with us for more updates and solutions. JEE Main 9th January Answer Key 2019 has been released by Resonance, Allen Kota, Career Point Coaching institutes on 9th January. Ea = 3.984 kJ/mol. Q21) Select the correct option : If f(x) is twice differentiable and continuous function in x [a, b] also f'(x) > 0 and f ''(x) < 0 and c [a, b] then is greater than. And Answer key ( ii ) C form precipitate with AgNO3 in the lassaigne extract of the most and... Are correct for moving charge as shown in figure ethylene glycol at its freezing point are... Of Cl–CH=CH–NO2 is more stable than resonance form of any other given compounds Determine activation energy in mol kJ/mol of... 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